Calculate the complete and net ionic equations, spectators and precipitates in 3Ca(NO3)2(aq) + 2Na3PO4(aq) = Ca3(PO4)2(s) + 6NaNO3(aq)
a = 3 (Ca(NO3)2) b = 2 (Na3PO4) c = 1 (Ca3(PO4)2) d = 6 (NaNO3) Step 4: Substitute Coefficients and Verify Result Count the number of atoms of each element on each side of the equation and verify that all elements and electrons (if there are charges/ions...
The reactions of Ca(NO3)2 + Na3PO4 in water and water/sodium bis(2-ethylhexyl) sulfosuccinate (AOT)/hydrocarbon microemulsions saturated CO2 with various molar ratios of water to surfactant R, oil phases, and surfactant concentrations were investigated by isothermal titration calorimetry. The ...
(1)Na2SO4溶液(Na2CO3):所加试剂为稀硫酸; 离子方程式为:2H++CO32=H2O+CO2↑; (2)Ca(NO3)2溶液(CaCl2):所加试剂为硝酸银溶 液;离子方程式为:Ag++Cl=AgCl↓; (3)FeSO4溶液(CuSO4):所加试剂为铁;离子方 程式为:Cu2++Fe=Fe2++Cu。 【答案】 (1)稀硫酸;2H++CO32=H2O+CO2↑;(2)硝酸 银...
Ba是+2价，所以SO4是-2价，计算方法就是正价与负价之和为0.Na是+1价，所以PO4为-3价，3乘以+1-X=0 X=—3 就这样算！ OH为-1价， NH4 为+1价，NO3为-1价， CLO为-1价， K2MnO4中MnO4为+2价， CO3为-2价。SO4
解:A.该电离方程式没有配平,正确的电离方程式应为:Na3PO4═3Na++3PO43-,故A错误;B.碳酸钙和硝酸发生复分解反应,生成硝酸钙和水和二氧化碳,该化学方程式书写完全正确,故B正确;C.铁和盐酸反应生成氯化亚铁和氢气,正确的化学方程式应为:Fe+2HCl═FeCl2+H2↑,故C错误;D.乙酸是弱酸,部分电离,需用可逆符号...
CaCO3 + C6H8O7*H2O = Ca3(C6H5O7)2 + CO2 + H2O K2S + Na2HPO4 = Na3PO4 + K3PO4 + H2S In + O2 = In2(O3) Zn + KNO3 + HCl = ZnCl2 + KCl + N2 + H2O H + F = FH Zn(NO3)2 + H3PO4 = HNO3 + Zn3(PO4)2 ...
Na(NO3) ℹ️ Lookup Complete Ionic Equation The complete (or total) ionic equation includes spectator ions. Write it by breaking all the soluble ionic compounds into their respective ions. Make sure that any subscripts are moved into the coefficient of the resulting ions and no atoms are lo...
(2)“酸浸”过程HNO3与Ca,F(PQ4)3反应的化学方程式如下,请补充完整□Ca, (PO_4) ,+□HNO3=□Ca(NO3)2+□+□HF个(3)“萃取 ”的目的是富集RE,但其余元素也会按一定比例进入萃取剂中。①通过3ROH +POCl1=(RO),PO+3HCl制得有机磷萃取剂(RO),PO,其中-1代表烃基,-R对(RO)3PO产率的影响如下...
以原硅酸四乙酯、四水硝酸钙(Ca(NO3)2·4H2)为原料,采用溶胶-凝胶法合成了SiO 2·CaO·P2O5玻璃和磷酸三乙酯(TEP,C6H15O4P)分别作为SiO2、CaO和P2O5的前体。制备了四种摩尔比不同的制剂(Ca/P:3-6-9-12)。每个制剂都是按照图1所示的流程图获得的。第一步,制备硝酸(HNO3≥65%)、水、乙醇(99.8%)和TEOS...