【题目】 c语言输入若干个整数输入是-1时,输入结束;后计算所有元素之和及平均值,并找出这些数的最大值和最小值 相关知识点: 试题来源: 解析 【解析】 #include stdio.h int main() { int sum = 0, cnt = 0, maxv, minv, v, flag=0; double avg; while (scanf("%d", & v)v_1=-1 { if...
include <stdlib.h> int main(){int max,min,num;printf("Input numbers,-1 to end:\n");scanf("%d",&num);max=min=num;while(num!=-1){ if(num>max)max=num;if(num<min)min=num;scanf("%d",&num);} printf("max:%d,min:%d\n",max,min);system("pause");return 0;} ...
printf("输入没正整数最大值");}
用C语言编程实现输入一个三位的正整数,求个十百位数的最大数,如输入836,最大数是八 只要输入的数不超过10位就行: #include <stdio.h> int mai C语言 从键盘输入10个整数,保存在一堆数组中,求这些整数中能被7整除的数组元素之和,将计算结果输出 #include <stdio.h>#include <stdlib.h>int main(){ 猜...
include <stdio.h>int main(){ int n, max, min; scanf("%d",&max); min=max; while(scanf("%d",&n)==1 && n>=0) if(max<n)max=n; else if(min>n)min=n; printf("%d %d\n",max, min); return 0;} ...
include <stdio.h>void main(){int num,i=0,j,arr[100]={0},sum=0,max;while(1){scanf("%d",&num);arr[i++]=num;if (num==0){break;}}max = arr[0];for (j=0;j0){sum += arr[j];}if (max<arr[j]){max = arr[j];}}printf("Sum:%d\n",sum);printf("Max:%d...
include "stdio.h"int main() {int n, sum=0, i=0, max, min;double ave;while(scanf("%d", &n) && n != 0) {if(i == 0) {max = min = n;}if(max < n) {max = n;}if(min > n) {min = n;}i++;sum += n;ave = sum * 1.0 / i;}printf("i = %d\...