第一个是计算闰年数，第二个计算当前是周几的相关函数
int day,month,year,sum,leap;printf("\npleaseinput year,month,day\n");scanf("%d,%d,%d",&year,&month,&day);switch( 【1】 )/*先计算某月以前月份的总天数*/{case 1:sum=0;break;case 2:sum=31;break;case 3:sum=59;break;case 4:sum=90;break;...
int GetDays(int nYear, int nMonth){ //参数越界检查(nMonth输入为1~12)if (nMonth <= 0 || nMonth > 12){ return 0;} //每个月的天数 int anMonthDay[12] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};//闰年的2月是29天 if((nYear % 4 == 0) && ...
#define杨int#define汤(Year,Days);if(#define周MonthStr[12][10]#define卫"September",...
int getStartDay(int, int); int getTotalNumberOfDays(int, int); int getNumberOfDaysInMonth(int, int); bool isLeapYear(int); int main() { int year,month;printf("请输入一个年份(例如: 2001): "); scanf("%d",&year); printf("请输入一个月份(1-12的数字): "); ...
int year){ return year%4==0&&year%100!=0||year%400=0;} int day_of_year(int year, int month, int day){ const int m[12]={31,28,31,30,31,30,31,31,30,31,30,31};int i,s=day;for(i=0;i<month-1;i++)s+=m[i];if(isLeapYear(year))s++;return s;} ...
百度试题 结果1 题目( )6.年A. monthB. dayC. year 相关知识点: 试题来源: 解析 C. year 题目要求选择与“年”相对应的英文单词。选项中,“year”意为“年”,与题目要求一致。因此,正确答案是C。反馈 收藏
printf("%d年是闰年\n", year );else printf("%d年是平年\n",year);system("pause");return 0;} int day(){ printf("Enter a date:");int month,date;int time;scanf("%d%d",&month,&date);switch(month){ case 1:time=date;break;case 2:time=31+date;break;case 3:time=...
#include<cstdio> int isRunNian(int year); int DiJiTian(int year,int month,int day); void swap(int *a,int *b); int main() { int year1,month1,day1; int year2,month2,day2; int sum=0; scanf("%d%d%d",&year
百度试题 结果1 题目【题目】月份( ) A. yearB. dayC. month相关知识点: 试题来源: 解析 【答案】C 【解析】 略反馈 收藏