int16_t 强转为uint16_t int32_t 强转为uint32_t#无符号转有符号如: uint8_t 强转为int8_t uint16_t 强转为int16_t uint32_t 强转为int32_t 举例: int32_t val = -121; uint32_t new = (uint32_t)val; printf("val = 0x%x, %d, new = 0x%x, %d\n", val, val, new, new);...
uint32_t htobe32(uint32_thost_32bits); uint32_t htole32(uint32_thost_32bits); uint32_t be32toh(uint32_tbig_endian_32bits); uint32_t le32toh(uint32_tlittle_endian_32bits); uint64_t htobe64(uint64_thost_64bits); uint64_t htole64(uint64_thost_64bits); uint64_t be...
代码很简单,直接上源码: #include<stdio.h>typedefunsignedcharuint8_t;typedefunsignedintuint32_t;uint32_ttest_val=0x12345678;intmain(){printf("test init value is:0x%x\n\r",test_val);// expected resultuint8_tval1=test_val&0xff;uint8_tval2=(test_val&0xff00)>>8;uint8_tval3=(test_va...
int main(){ uint32_t u32=0x6789ABCD,a32,b32; uint16_t u16=0x89AB, a16,b16=0x1234; uint8_t u8=0x12,a8,b8=0x34,c8=0x56,d8=0x78; printf("This is a program of Hexadecimal conversion.\n\n"); multiple_data DATAP; DATAP=u32_turn_Two_HEX(u32); printf("The following is th...
typedefunsigned__int32uint32_t 1. 其实就是无符号的32位int型数据。对于编程中出现的“uint32_t没有被定义”的错误,只需要将这行代码加载程序中就可以了 那么问题来了,对于这个类型的变量如何输入与输出呢。。。 下面给个例子(vc6.0) #include<stdio.h> ...
uint32_t strToUInt32(const char *str); int main() { // 输入待转换的数字字符串 const char *inputStr = "12345"; // 调用字符串转数字函数并获得返回结果 uint32_t result = strToUInt32(inputStr); // 输出转换后得到的数字 printf("转换结果:%u\n", result); return 0; } ``` 4.2 算法...
uint32_t a;int16_t b,c;b = (int16_t)a;c = (int16_t)(a>>16);
16 typedef unsigned char uint8_t; 17 typedef unsigned short int uint16_t; 18 #ifndef __uint32_t_defined 19 typedef unsigned int uint32_t; 20 # define __uint32_t_defined 21 #endif 22 #if __WORDSIZE == 64 23 typedef unsigned long int uint64_t; ...
if((int32_t)(((uint32_t)x-(uint32_t)minx)|((uint32_t)maxx-(uint32_t)x))>=0)......