fmod - 浮点数取余函数 fmod 函数用于计算两个浮点数相除的余数。 #include <cmath> #include <iostream> int main() { double numerator = 12.5; double denominator = 3.2; std::cout << "12.5 除以 3.2 的余数是: " << std::fmod(numerator, denominator) << std::endl; return 0; } 输出:12.5...
std::fmax: 返回较大的值; std::fmin: 返回较小的值; std::fpclassify:为浮点值归类,返回一个类型为int的值; std::isfinite: 检测是否是有限值; std::isinf: 检测是否是无穷大值; std::isnan: 检测是否是非数型; std::isnormal: 检测是否是normal值,neitherinfinity, NaN, zero or subnormal; std::s...
{ // std::fmod: Returns the floating-point remainder of numer/denom(rounded towards zero) printf("fmod of 5.3 / 2 is %f\n", std::fmod(5.3, 2)); // fmod of 5.3 / 2 is 1.3 printf("fmod of 18.5 / 4.2 is %f\n", std::fmod(18.5, 4.2)); // fmod of 18.5 / 4.2 is 1.7...
std::cout << "abs(-5) = " << abs(-5) << std::endl; std::cout << "fmod(5.3, 2) = " << fmod(5.3, 2) << std::endl; // 指数和对数函数 std::cout << "exp(1) = " << exp(1) << std::endl; std::cout << "log(2.71828) = " << log(2.71828) << std::endl;...
#include<string>#include#include<fmod.hpp>typedefstd::map<std::string, FMOD::Sound*> SoundMap;classSimpleAudioManager{public:SimpleAudioManager(); ~SimpleAudioManager();voidUpdate(floatelapsed);voidLoad(conststd::string& path);voidStream(conststd::string& path);voidPlay(conststd::string& path);...
6. fmod,fmodf,fmodl 6.1 函数说明 6.2 演示示例 #include<stdio.h>#include<math.h>intmain(){doublex=10.24,y=5.63;printf("fmod(%.2lf, %.2lf) = %.20lf\n",x,y,fmod(x,y));floatxf=5.63,yf=2.89;printf("fmodf(%.2f, %.2f) = %.20f\n",xf,yf,fmodf(xf,yf));longdoublexL=2.89...
但是,大多数代码不受影响 - 例如,std::future_status::ready 仍将编译。 explicit operator bool() 比运算符 unspecified-bool-type() 更严格。 explicit operator bool() 允许到 bool 的显式转换 - 例如,在给定 shared_ptr<X> sp 的情况下,bool b(sp) 和static_cast<bool>(sp) 都有效 - 允许对 bool...
除标准错误流 (stderr) 之外,输出流在输出至文件时缺省情况下缓冲,在输出至终端时采用行缓冲。标准错误输出流 (stderr) 在缺省情况下不缓冲。 缓冲的输出流保存多个字符,然后将这些字符作为块进行写入。未缓冲的输出流将信息排队,以便立即在目标文件或终端上写入。行缓冲的输出将输出的每行排队,直至行完成(请求换...
//Example will output remainder of 12/5 (2) #include <cmath> #include <iostream> using namespace std; int main() { cout<<"The remainder of 12/5: "<<fmod(12/5); }Other Functions Popular pages Jumping into C++, the Cprogramming.com ebook How to learn C++ or C C Tutorial ...
void * operator new(std::size_t, std::size_t); void operator delete(void*, std::size_t) noexcept; The problem occurs because of the match in function signatures between a placement delete operator you've defined, and the new global sized delete operator. Consider whether you can use ...