素数又叫质数(prime number),有无限个。质数定义为在大于1的自然数中,除了1和它本身以外不再有其他因数。 二、代码实现 1.主函数构建 代码语言:javascript 代码运行次数:0 AI代码解释 intmain(){int n=0;int count=0;printf("请输入一个整数n:");scanf("%d",&n);printf("从%d到%d的范围内所有的素数:...
Program to Check Prime Number #include <stdio.h> int main() { int n, i, flag = 0; printf("Enter a positive integer: "); scanf("%d", &n); // 0 and 1 are not prime numbers // change flag to 1 for non-prime number if (n == 0 || n == 1) flag = 1; for (i = 2...
C program to find the frequency of a character in a string C program to read a string and print the length of the each word C program to eliminate/remove all vowels from a string C program to eliminate/remove first character of each word from a string C program to read n strings and...
In this program, the while loop is iterated ( high-low-1) times. In each iteration, whether low is a prime number or not is checked, and the value of low is incremented by 1 until low is equal to high. Visit this page to learn more about how to check whether a number is prime ...
if(prime)/*是素数*/ { printf("%6d", m); i ++; if(i % 5 == 0) printf("\n"); } } if(i % 5 != 0) printf("\n"); } 运行结果: 第二种采用筛选法来求素数: 使用筛选法求素数的基本思想是:把某一范围内的正整数按从小到大的顺序排列,宣布 1 不是素数,把它筛掉。然后从剩下的...
Write a program in C to check whether a number is a prime number or not using the function. Pictorial Presentation: Sample Solution: C Code: #include<stdio.h>intPrimeOrNot(int);intmain(){intn1,prime;printf("\n\n Function : check whether a number is prime number or not :\n");print...
C program to count the frequency of each element in an array– In this article, we will detail in on the several means to count the frequency of each element in an array in C programming. Suitable examples and sample programs have also been added so that you can understand the whole thin...
Output: All prime factors of 75 are: 3 5 5 Visual Presentation: Sample Solution: C Code: #include<stdio.h>#include<stdlib.h>// Main functionintmain(void){// Declare and initialize the variable 'n' to find its prime factorsintn=75;// The number for which prime factors are to be f...
printf(“input the number you want to find x:”);scanf(“%d”, &x );for(i=0;i<10;i++)if( x==a[i] )break;if( i<10 )printf(“the pos of x is:%d\n”,i);else printf(“can not find x!\n”);}7.程序读入20个整数,统计非负数个数,并计算非负数之和。
using System;publicclassHappyProgram{publicstaticvoidMain(){ Console.WriteLine("Enter a number: ");intYourNumber=Convert.ToInt16(Console.ReadLine());if(YourNumber >10) Console.WriteLine("Your number is greater than ten");if(YourNumber <=10) Console.WriteLine("Your number is ten or smaller"...