Finally, the value of sum is printed on the screen. The program output is shown below: #include<stdio.h>void main(){ int n,j,sum=0; clrscr(); printf("Enter the Number : "); scanf("%d",&n); for(j=1;j<=n;j++) {
/*C program to calculate sum of first N natural numbers.*/#include<stdio.h>intmain(){intn,i;intsum;printf("Enter the value of N:");scanf("%d",&n);sum=0;for(i=1;i<=n;i++)sum+=i;printf("Sum is:%d\n",sum);return0;} ...
3)for loop iterates from i=0 to i<n. If the remainder of a[i]/2 is equal to zero then increase the even value by 1. Otherwise, increase the odd value by 1. 4)After all iterations of for loop print the total number of even elements in an array and print total number of odd ...
C program to find sum of all numbers from 0 to N without using loop #include<stdio.h>intmain(void){intn,sum;//input value of nprintf("Enter the value of n:");scanf("%d",&n);//initialize sum with 0sum=0;//use formula to get the sum from 0 to nsum=n*(n+1)/2;//print...
Input number of terms : 5 The even numbers are :2 4 6 8 10 The Sum of even Natural Number upto 5 terms : 30 Flowchart: For more Practice: Solve these Related Problems: Write a C program to display even natural numbers up to n and compute their product instead of sum. ...
原文:https://beginnersbook.com/2014/06/c-program-to-check-armstrong-number/ 如果数字的各位的立方和等于数字本身,则将数字称为阿姆斯特朗数。在下面的 C 程序中,我们检查输入的数字是否是阿姆斯特朗数。 #include<stdio.h>intmain(){intnum,copy_of_num,sum=0,rem;//Store input number in variable numpri...
Sum: 3521 Flowchart: For more Practice: Solve these Related Problems: Write a C program to sum all numbers between two given integers, excluding those that are multiples of a user-specified number. Write a C program to calculate the sum of all prime numbers between two inte...
{ static char a[ ]=”Program”, *ptr;for(ptr=a, ptr<a+7; ptr+=2)putchar(*ptr);}运行结果为: Porm首先定义一个字符型数组a,并对a进行初始化; 然后定义字符型指针变量p;执行for语句 ptr=a为表达式1,将数字a的地址赋给ptr;表达式2(循环条件)ptr...
sum=num1+num2; /* Performs addition and stores it in variable sum */ printf("Sum: %d",sum); /* Displays sum */ return 0; } 输出: Enter two integers: 12 11 Sum: 23 4、C语言实现两个小数相乘 /*C program to multiply and display the product of two floating point numbers entered ...
b)Store the count value at b[i].i.e b contains the count numbers of each element of the array. 4)Print the each element along with their count number as printf(“no of %d is %d \n”,a[i],b[i]) using for loop from i=0 to i<n.Here Print Method ...