temp for (first=0; str[first]!='\0'; first++) { // if any character in str and reverse str i.e. temp is unequal, break the loop if(str[first]!=temp[first]) { printf("%s is not a palindrome!\n",str); break; } } // if loop did not break str and reverse str i.e. ...
{printf("Give word is a palindrome"); }if(flag==1) {printf("This is NOT a palindrome word"); }return0; } The algorithm you are using in the first program involves comparing each letter to every other letter which does not help in determining if the number is a palindrome and it do...
C program for palindrome without using string functions #include <stdio.h> intmain() { chartext[100]; intbegin,middle,end,length=0; gets(text); while(text[length]!='\0') length++; end=length-1; middle=length/2; for(begin=0;begin<middle;begin++) ...
回文(palindrome)是一个正读和反读都完全一样的单词,如level或noon.写一个谓词函数IsPalindrome(str), 如果字符串str是回文,则返回TRUE.回文的概念可以扩展到一个完整的语句,只要忽略标点符号和大小写的差异即可。例如:语句 Madam,i'm Adam 是一个回文语句,因为如果你仅看字母,忽略任何大小写的区别,正读和反读...
bool isItAPalindrome (char * aString); void printSuffixes (char * aString, int whichWord, char * desiredSuffix); // Custom Functions int checkPunctuation(char x); // Main int main(int argc, char **argvs) { if(argc < 2) {
10个经典的C语言面试基础算法及代码,算法是一个程序和软件的灵魂,作为一名优秀的程序员,只有对一些基础的算法有着全面的掌握,才会在设计程序和编写代码的过程中显得得心应手。本文是近百个C语言算法系列的第二篇,包括了经典的Fioacci数列、简易计算器、回文检查、质数检
C program to find next prime palindrome: In this code user will enter a number(say n) and we have to find a number greater than n which is a palindrome as well as prime. For example,if the input is 7 then output will be 11 as it is prime as well as palindrome, if input is 21...
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printf("%d is a palindrome.",n); else printf("%d is not a palindrome.",n); return 0; } 结果输出: Enter an integer: 12321 12321 is a palindrome. 3、质数检查 注:1既不是质数也不是合数。 源代码: /* C program to check whether a number is prime or not. */ ...
printf("%d is a palindrome.",n); else printf("%d is not a palindrome.",n); return 0; } 结果输出: Enter an integer: 12321 12321 is a palindrome. 3、质数检查 注:1既不是质数也不是合数。 源代码: /* C program to check whether a number is prime or not. */ ...