在C/C++编程中,“incomplete type is not allowed”是一个常见的编译错误,通常表示编译器在处理代码时遇到了一个未完整定义的类型。下面我将按照你的要求,详细解释这个错误,并提供相关的解决方法和示例。 1. 错误信息含义 “incomplete type is not allowed”错误表明编译器在编译过程中遇到了一个未完整定义的类型...
EINT.C(4): error: #70: incomplete type is not allowed 结构体声明在是不能被extern的，如果多个文件中用了一个同结构体，只想声明一次 需要将结构体在头文件中定义，初始化可以放在.c中.EINT.C(4): error: #65: expected a ";"这是缺少了；EINT.C(24): warning: At end of sourc...
void a(void) //函数a的实体 { b(); //调用函数b } void b(void) //函数b的实体 { ... } error: #70: error: #70: incomplete type is not allowed 原来是重复定义了,包含了两次的psock的定义,所以才会出现这种情况。因为我发现psock和pt是一样定义的,但是pt是不报错的,所以我就试图删除头文件...
externx;/* Non-compliant – implicit int type */externint16_tx ;/* Compliant – explicit type */consty ;/* Non-compliant – implicit int type */constint16_ty ;/* Compliant – explicit type */staticfoo(void);/* Non-compliant – implicit type */staticint16_tfoo(void);/* Compliant ...
具体来说，在您的例子中，编译器不知道struct node有next，所以
type_traits(1110): error C2139: 'D': an undefined class is not allowed as an argument to compiler intrinsic type trait '__is_base_of' ..\t331.cpp(14): note: see declaration of 'D' ..\t331.cpp(10): note: see reference to class template instantiation 'std::is_base_of<T,U>'...
void a(void) //函数a的实体 { b(); //调用函数b } void b(void) //函数b的实体 { ... } error: #70: error: #70: incomplete type is not allowed 原来是重复定义了,包含了两次的psock的定义,所以才会出现这种情况。因为我发现psock和pt是一样定义的,但是pt是不报错的,所以我就试图删除头文件...
Compiler error C2625 'identifier': illegal union member; type 'type' is reference type Compiler error C2626 'identifier': a private/protected data member is not allowed in an anonymous struct/union Compiler error C2627 'function': member function not allowed in anonymous union Compiler error C...
Cause: A host variable used in a SQL statement was not declared properly. Some possible causes follow: It was not declared in the DECLARE section. Its datatype is not supported. Its name is misspelled. It is a COBOL group item; in Pro*COBOL, only elementary items are allowed in ...
int f(void) { unsigned short us; unsigned char uc; return uc < us; } In this example, both automatics are either promoted to int or to unsigned int, so the comparison is sometimes unsigned and sometimes signed. However, the C compiler does not warn you because the result is the same...