在Rust与C语言中，针对u128、i128数据类型在x86-32和x86-64架构上的对齐方式，长期以来存在不一致。这种不一致来自于两个实例的对齐要求不同，在C语言中，__int128（相当于Rust的u128、i128）的对齐要求遵循该平台应用程序二进制界面（ABI）的规范，代表着在x86-64系统上，__int128的对齐可能被要求为16字节，目...
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Rust缺少C语言中的int、long、unsigned和其他具有实现定义大小的类型。相反,Rust的原生整数类型是精确大小的类型:i8、i16、i32、i64和i128分别是8、16、32、64和128位的有符号整数,而u8、u16、u32、u64和u128是其无符号变体。Rust还提供了isize和usize,它们对应于intptr_t和uintptr_t11。对齐要求与C语言完全...
long double _Complex ldc = 5+5i; __int128_t i128 = 0; __uint128_t ui128 = 3.4028236692093846346337460743177e+38; void *ptr = 0; */ import "C" import "fmt" import "unsafe" func main() { fmt.Println(C.b) fmt.Println(C.c) fmt.Println(C.sc) fmt.Println(C.usc) fmt.Println(...
{printf("%llu",d1);printf("%019llu",d0);}else{printf("%llu",d0);}}staticvoidprint_i128(...
Most of our Rust-specific overflowing intrinsics currently return (i128, bool), which is not guaranteed to have a stable ABI. Switch to returning the overflow via a mutable parameter and only directly returning the integer result. __rust_i128_mulo now matches the function signature of __mulot...
Prints8. While the following C program: #include<stdio.h>structfoo{unsigned__int128t; };intmain() {printf("Align: %ld\n", _Alignof(structfoo)); } Prints16on the same system. This is pretty unexpected, and means that i128 / u128 are not really usable for FFI / alignment purposes....
Test ui128::c::clang_calls_gcc::i128_val_in_2_perturbed_small passed Test ui128::c::clang_calls_gcc::i128_val_in_3_perturbed_small passed Test ui128::c::clang_calls_gcc::i128_val_in_0_perturbed_big failed!test57arg3 field0mismatchcaller:[30,31,32,33,34,35,36,37,38,39,3A,...
std::ostream &operator<<(std::ostream &os, i128 n) {if(n ==0)returnos <<0; string s;boolnegative =false;if(n <0) { negative =true; n = -n; }while(n >0) { s +=char('0'+ n %10); n /=10; }if(negative) os <<'-';reverse(s.begin(), s.end()); ...
23.心脏是血液循环的动力器官,每分钟输出的血量叫心输出量。16腓肠肌C A口时 E \I128I普通人A IⅡ经常锻炼的人D4B血管050 100 150 200 250心率(次/min)图1图2图3(1)心脏主要由肌肉组成,推动着血液在人体内按一定方向循环流动。①在图1所示心脏四腔中,AB一侧收集来自全身的血液,再将这些血液泵入肺动脉。