6, 3, 8, 4}; int size = sizeof(array) / sizeof(array[0]); int max = array[0]; int min = array[0]; for (int i = 1; i < size; i++) { if (array[i] > max) { max = array[i]; } if (array[i] < min) { min = array[i]; } } printf("最大值:%d\n", max...
max; } intmain(){ int arr[] = {3, 5, 1, 8, 2}; int size = sizeof(arr) / sizeof(arr[0]); int max = findMax(arr, size); printf("The maximum value in the array is: %d\n", max); return 0; } 复制代码 这段代码中,通过定义一个函数findMax来查找数组中的最大值,然后在ma...
nPave[0] =0;intmaxPave = nPave[nPave.FindMax(0, [](int,intcount) {returncount; })];if(maxPave ==0) { pave =1+ parentChit->random.Rand(WorldGrid::NUM_PAVE -1); }else{ pave =1+ ArrayFindMax(nPave.Mem()+1, nPave.Size() -1,0, [](int,intcount) {return-count; });...
解析 find max(a,sizeof(a)/sizeof(int)) max=array[0],第一处,填入findmax函数,其中第一个参数肯定是数组名,第二个参数是数组长度,可以用sizeof(a)/sizeof(int)表示,第二处,找最大值,首先默认第一个元素是最大值,所以要填:max=array[0]
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findSecondMaxValueInArray(int a[], int n) { int i; // 数组元素索引(下标) int max1 = 0; // 最大值元素下标 int max2 = 0; // 次大值元素下标 for (i = 0; i < n; ++i) { if (a[max1] < a[i]) { max2 = max1; // 原来最大值为新的次大值 max1 = i; // 当前...
max_suba[1]=max_right; } } max_suba[2]=(left_sum+right_sum); return max_suba; } /*** * * function find_maximum_subarray() * * args * A[] inttype array * low inttype the lower index of A * hihg inttype the high index of A * * return...
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