inline and constexpr Function Templates inline 和 constexpr 关键字放在 template argument 之后，函数返回值之前，如下 // oktemplate <typename T> inline T in(const T &, const T &)//errorinline template <typename T> T min(const
Compiler error C3615 constexpr function 'function' cannot result in a constant expression Compiler error C3616 Obsolete. Compiler error C3617 initializers of structured bindings must be of array or non-union class type; type 'type_name' is not permitted ...
int constexpr() {return 1;} 可移动类型不能为常量 当函数返回预期要移动的类型时,其返回类型不得为 const。 已删除复制构造函数 下面的代码现在生成错误 C2280:"S::S(S &&)":正在尝试引用已删除的函数。 C++ 复制 struct S{ S(int, int); S(const S&) = delete; S(S&&) = delete; }; S...
structX{inlinestaticintn=1;};structY{constexprintn=1;};// 隐式 inline
You can't inline a recursive function! In fact, any time the function argument is itself a constexpr, it can be computed at compile time.What else can go in a constexpr function?A constexpr function can have only a single line of executable code, but it may contain typedefs, using ...
constexpr intfoo(int i){returni+5;}std::array<int,foo(5)>arr;// OK 5. 宏和内联(inline)函数的比较? 1). 首先宏是C中引入的一种预处理功能; 2). 内联(inline)函数是C++中引入的一个新的关键字;C++中推荐使用内联函数来替代宏代码片段; ...
A reinterpret_cast is illegal in a constexpr function. The Microsoft C++ compiler would previously reject reinterpret_cast only if it were used in a constexpr context. In Visual Studio 2019, in all language standards modes, the compiler correctly diagnoses a reinterpret_cast in the definition of...
__aicore__ inline void Process() { // loop count need to be doubled, due to double buffer constexpr int32_t loopCount = TILE_NUM * BUFFER_NUM; // tiling strategy, pipeline parallel for (int32_t i = 0; i < loopCount; i++) { CopyIn(i); Compute(i); CopyOut(i); } } 根...
int constexpr() {return 1;} Movable types can't be const When a function returns a type that's intended to be moved, its return type should not be const. Deleted copy constructors The following code now produces C2280 'S::S(S &&)': attempting to reference a deleted function: C++...
int constexpr() {return 1;} Movable types can't be const When a function returns a type that's intended to be moved, its return type should not be const. Deleted copy constructors The following code now produces C2280 'S::S(S &&)': attempting to reference a deleted function: C++...