在C++当中,我们在函数参数后面加上const,如上面代码fun_2()那样,则将整个成员变成常量成员,即将*this, 转换成const *this.
我想到的一种办法是可以直接在内部将const修饰符去掉,具体如下: out<<(const_cast<Point3d*>(this))->GetX()<<""<<(const_cast<Point3d*>(this))->GetY()<<""<<(const_cast<Point3d*>(this))->GetZ()<<std::endl; 参考文献: 1.Error C2662, cannot convert‘this’ pointer from‘const class...
C++ Error C2662 cannot convert 'this' pointer from 'const *' 2018-05-14 17:32 − ---恢复内容开始--- 这个错误在于一点:常量对象只能调用常量成员(函数\变量),不能调用非常量成员。另一方面,非常量对象,既可以调用常量成员,又可以调用非常量成员。 class A { public: void fun_1() { std::cout...
classCMyClass{public:explicitCMyClass(intiBar)throw(){ }staticCMyClassget_c2(); };intmain(){ CMyClass myclass =2;// C2440// try one of the following// CMyClass myclass{2};// CMyClass myclass(2);int*i;floatj; j = (float)i;// C2440, cannot cast from pointer to int to ...
针对您提出的“error c2440: '=' : cannot convert from 'const unsigned short *' to 'const char *'”问题,我们可以从以下几个方面进行详细分析和解答: 1. 理解错误c2440的具体含义 错误c2440通常表示在赋值过程中,编译器无法将源类型转换为目标类型。在这个具体的错误中,编译器无法将const unsigned short ...
在C++中,_tcschr()被重载,以TCHAR*或const TCHAR*作为输入。要返回non-constTCHAR*,您必须调用non-const重载,这意味着放弃optstring的const,例如: TCHAR *temp = _tcschr(const_cast<TCHAR*>(optstring), c); 或者根据文档定义_CONST_RETURN: 在C语言中,这些函数的第一个参数是const指针。在C++中,有两个重...
Compiler error C2662 'function': cannot convert 'this' pointer from 'type1' to 'type2' Compiler error C2663 'function': no overloaded function has valid conversion for 'this' pointer Compiler error C2664 'function': cannot convert argument number from 'type1' to 'type2' Compiler error C26...
Cannot open multiple items from this location. Try selecting a single item instead cannot open source file "stdafx.h" cant find declaration of structure in .h file capturing and injecting click events into a win32 GUI with an external program Cast unsigned char (uint8 *) pointer to unsigned...
c1xx : fatal error C1083: Cannot open source file [Even though the file exists] C2275: illegal use of this type as an expression Calling a C++ Class Constructor from a DLL Calling a dll function using __stdcall Can I check if a pointer is valid? Can I use pointers as key in st...
cannot convert parameter 1 from 'char' to 'const char *这句话的意思就是说：不能讲参数1的char类型转换成一个地址类型，因为我们通过数组保存字符串，一般来说我们知道数组名就可以访问这个字符串，因为数组名是数组第一个元素的地址，他们在内存中是紧挨着的。因此你要判断字符串是否相等，要传递...