BST_traverse(中序遍历,前序遍历,后序遍历) refer to:https://www.algoexpert.io/questions/BST%20Traversal&& leetcode &&力扣 分别使用前序遍历中序遍历后序遍历的方法遍历搜索二叉树 1importjava.util.*;23classProgram {4publicstaticList<Integer> inOrderTraverse(BST tree, List<Integer>array) {5if(tree...
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publicvoidinOrder(){ System.out.print("inOrder traversal with recursion:"); inOrder(root); System.out.println(); } //递归 privatevoidinOrder(BiNoderoot){ if(root==null)//访问结点 return; inOrder(root.left); System.out.print(root.data);//访问结点 inOrder(root.right); } //后序遍历...
前序遍历(preorder traversal):当前结点,然后左子树,然后右子树 中序遍历(inorder traversal):左子树,当前结点,然后右子树 后序遍历(postorder traversal):左子树,右子树,然后当前结点 广度优先,第一层,第二层,第三层的所有结点 深度优先 删除 第一步要找到需要被删除的结点和它的父节点 第二步考虑如果被删除结...
// BST에서 inorder traversal을 수행하는 함수 void inorder(Node* root) { if (root == nullptr) { return; } inorder(root->left); cout << root->data << " "; inorder(root->right); } // `curr`에 뿌리를 둔 하위 트리에서 최소값 노드...
printInorderTraversal(root.right); } } Call the above method in the main method: BST Insertion Iterative To insert a Node iteratively in a BST tree, we will need to traverse the tree using two pointers. public static TreeNode insertionIterative(TreeNode root, int value) { ...
这个想法是使用Morris Traversal。在此遍历中,我们首先创建指向 Inorder 后继树的链接并使用这些链接打印数据,最后还原更改以恢复原始树。更多细节见this。下面是这个想法的实现。 C++ // C++ program to find k'th largest element in BST #include<bits/stdc++.h> ...
// Create an empty queue for level order traversal queue<Node*>q; q.push(root); while(!q.empty()) { intnodeCount=q.size(); while(nodeCount>0) { Node*node=q.front(); cout<<node->data<<" "; q.pop(); if(node->left) ...
printf ( "Inorder traversal of the constructed tree: \n" ); printInorder(root); return 0; } Java // Java program to construct BST from given preorder // traversal // A binary tree node class Node { int data; Node left, right; ...
org/in order-preventer-后继者-给定-key-bst/最近在电商公司面试遇到一个问题。面试官问了以下问题: 有一个 BST 给出了根节点,关键部分只有整数。每个节点的结构如下:C++struct Node { int key; struct Node *left, *right ; }; Java 语言(一种计算机语言,尤用于创建网站)...