f(1)=1+a+b+c=-2;(2)a=c;b=-2c-3;f′(x)=3x²+2cx-2c-3=(3x+2c+3)(x-1)=3(x+(2c+3)/3)(x-1)=0;当-(2c+3)/3≤1,即c＞-3时；单调增区间为[1，﹢∞﹚∪（﹣∞，-(2c+3)/3];单调减区间为[-(2c+3)/3,1];当-(2c+3)/3≥1,即c＜-3时...