8i-2j 向量的加法遵循对应坐标相加的规则。 对于向量 **AB = 3i - 4j**,其对应分量为 **i 方向 3** 和 **j 方向 -4**。 对于向量 **CD = 5i + 2j**,其对应分量为 **i 方向 5** 和 **j 方向 2**。 将两个向量的对应分量相加: - **i 方向总和**:3 + 5 = 8 - **j 方向...
设\(i,j\)为一组标准正交基,已知(AB)=3i-2j,(BC)=4i+j,(CD)=8i-9j.若(AD)=4a,求a在基\(i,j\)下的坐标.
又i．j是两个不共线向量，所以存在唯一实数k，使得：向量BD=k*向量AB 即 -3i +(1-λ)j=k(3i+2j)移项整理可得：(3k+3)i+(2k-1+λ)j=0 要使上式成立，须使得：3k+3=0且2k-1+λ=0 解得：k=-1，λ=1-2k=3 所以：若ABD三点共线，实数λ=3 ...
3i), indicating that ABHD5 does not alter β-Catenin stability. Consistent with this result, chromatin immunoprecipitation (ChIP)-qPCR assays using anti-β-Catenin and anti-TCF4 antibodies showed that ABHD5 knockdown did not increase the binding of either β-Catenin or TCF4 to the MET promoter...
BD向量=CD向量-CB向量=-3i+(1-λ)j A,B,D三点共线,则AB向量=k*BD向量，看为常数 3=-3*k 2=(1-λ)*k 解得k=-1，λ=3 AB
i、j是两个不共线的向量,已知(AB)=3i+2j,(CB)=i+λj, (CD)=-2i+j,若 A、B、D三点共线,试求实数λ的值15.已知向量a=(1,2),向量b=(-3,2).(1)若向量km+b与向量a-3b垂直,求实数B的值;(2)当B为何值时,向量km+b与向量a-3b平行并说明它们是同向还是反向. ...
代数 平面向量 平行向量(共线) 平行向量的计算 平面向量的基本定理 平面向量基本定理的应用 试题来源: 解析 由题意知(AB)=3i+2j (BD)=(CD)-(CB)=-2i+3j- ( (i+λ j) )=-3i+ ( (3-λ ) )j ∵ A,B,D三点共线则 (AB)=k(BD) 即3=k ( (-3) ) 2=k ( (3-λ ) ) ...
Chemotherapy combined with immunotherapy has improved the treatment of certain solid tumors, but effective regimens remain elusive for pancreatic ductal adenocarcinoma (PDAC). We conducted a randomized phase 2 trial evaluating the efficacy of nivolumab (
所以AC=AB+BC=i+2j+3i-j=4i+j AD=AC+CD=4i+j-4i+j=2j 所以AD=2j 希望对你有帮助
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