百度试题 结果1 题目过点(4,-1,-2)且与平面π:2x-3y+7z=16垂直的直线方程是-→_-→-.2.a+b-5=0.5+(4x_3)/7 相关知识点: 试题来源: 解析 (x-4)/2=(y+1)/(-3)=(z+2)/7 反馈 收藏
(向量代数与空间解析几何)直线2x-3y-7z+8=0 x+y-z-2=0 与直线2x-5y+z+2=0 x-5y+z+7=0的位置关系是 A. 异面 B. 相交于一点
Examine the consistency of the system of equations :x+3y=5,2x+6y=8 View Solution Examining consistency and solvability, solve the following equation by matrix method. 2x-y+z=4 x+3y+2z=12 3x+2y+3z=16 View Solution Exams IIT JEE
2x-3y+7z=8 (2)6x+2=3(y+6z)即6x-3y-18z=-2 (3)(1)×3+(2)17x+z=29 (4)(3)-(2)4x-25z=-10 (5)(4)×25+(5)429x=715 x=5/3 z=29-17x=2/3 y=17+2z-5x=10
列出增广矩阵，用高斯消元法求解：| 2x -3y -7z -8 | | 2x -3y -7z -8 | | 2x -3y -7z -8 | | x y -z 2 | ---> | x y -z 2 | ---> | 0 0 z 27/4 | | 2x -5y z -...
解方程组:3x+15y+7z=6,2.解方程组:2x-2y-3z=5,4x-9y+4z=9.2x-3y-4z=4.3x+y-4z=13,2R1+R2+R3=4,3.解方程组:5x-y+3z=5,4.解方程组:R1+2R2+R3=2,x+y-z=3.R1+R2+2R3=6.5.解方程组: (5x-(1-11y))/8=(5y-6x+2)/9=(3x+4y+7)/6896x+2y=5,①y+2z=8,②6...
②①*2+②*3 得:11x-33z=0解得:x=3z把x=3z代入方程②得:3z-7z+2y=0解得:y=2z把x=3z,y=2z代入(5x+2y-z)/(2x-3y-10z) (5x+2y-z)/(2x-3y-10z) =(5*3z+2*2z-z)/(2*3z-3*2z-10z) =(15z+4z-z)/(6z-6z-10z) =(18z)/(-10z)9=-9/5 【三元一次方程及...
相似问题 解方程组2x-3y+4z=2,4x+y+7z=3,8x-2y+3z=-5 二元一次方程组 2x-3y+4z=12 x-y+3z=4 4x+y-3z=--2 由方程组x−2y+3z=02x−3y+4z=0,可得x:y:z等于_. 特别推荐 热点考点 2022年高考真题试卷汇总 2022年高中期中试卷汇总 2022年高中期末试卷汇总 2022年高中月考试卷汇总 ...
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给岀的方程组是：2x＋y一7z＝10①，z＝一2x＋3y②，x一2y＋3z＝0③。②代入①得2x＋y一7（一2x＋3y）＝10，16x一20y＝10，8x一10＝5④，②代入③得x一2y＋3（一2x＋3y）＝0，一5x＋7y＝0，y＝5x／7⑤代入四得 8x一10（5x／7）＝5，6x／7＝5，解之得：x＝35／6，代入⑤得y...