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(2S-反)-[18-羧基-20-(羧甲基)-13-乙基-2,3-二氢-3,7,12,17-四甲基-8-乙烯基-21H,23H-卟吩-2-丙酸酯(5-)-N21,N22,N23,N24]镁酸酯(3-)性质、用途与生产工艺 (2S-反)-[18-羧基-20-(羧甲基)-13-乙基-2,3-二氢-3,7,12,17-四甲基-8-乙烯基-21H,23H-卟吩-2-丙酸酯(5-)-N21,...
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英文名称: hydrogen [3S-(3alpha,4beta,21beta)]-[14-ethyl-13-formyl-21-(methoxycarbonyl)-4,8,18-trimethyl-20-oxo-9-vinylphorbine-3-propionato(3-)-N23,N24,N25,N26]cuprate(1-) 英文同义词: hydrogen [3S-(3alpha,4beta,21beta)]-[14-ethyl-13-formyl-21-(methoxycarbonyl)-4,8,18-trim...
英文名称: Copper, [2,3,7,8,12,13,17,18-octabromo-5,10,15,20-tetraphenyl-21H,23H-porphinato(2-)-κN21,κN22,κN23,κN24]-, (SP-4-1)- CAS No.: 131214-87-4 分子式: C44H20N4CuBr8 分子量: 1307.43 如需查看该化合物的详细结构式,mol文件,smile,InChi 请点击:Copper, [2,3,...
等差数列\( (a_n) \)中,(a_1)+(a_2)+(a_3)=-24,(a_(18))+(a_(19))+(a_(20))=78 ,则此数列前20项的和等于(&
得a_1+a_(20)= (-24+78)3=18 所以S_(20)= (a_1+a_(20))2*20=180 故答案为:180 由a_1+a_2+a_3=-24,a_(18)+a_(19)+a_(20)=78,由等差数列的性质可得a_1+a_(20)= (-24+78)3=18,再由前n项和公式求解.本题主要考查等差数列中项性质的推广及前n项和公式....
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Synonyms:dipotassium [3S-(3alpha,4beta,21beta)]-[21-carboxy-14-ethyl-4,8,13,18-tetramethyl-20-oxo-9-vinylphorbine-3-propionato(4-)-N23,N24,N25,N26]cuprate(2-) CAS:72984-32-8 MF:C34H30CuK2N4O5 MW:716.3684 EINECS:277-165-2 ...
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