(4)根据二力平衡及相互作用力有:F_压=G=mg=3\times 10^3kg\times 10N/kg\times 3\times 10^4N P_2={{F_压}\over{S} }={{3\times 10^4N}\over{0.06m^2} }=5\times 10^5Pa (1)根据公式F=G=mg计算浮力。 (2)根据公式P=\rho gh计算压强。 (3)根据公式W=Fs计算做功大小。 (4)首先计...
为了便于识别和美观,要求现场手写字尽量符合标准字体模板(Times New Roman)的要求。标准字体模板如表4-241所示。 表4-241 标准字体模板 0 1 2 3 4 5 6 7 8 9 A B C D E F G H I J K L M N O P Q R S T U V W X Y Z 字的大小可根据数字或字母的数量灵活处理。当填写有汉字的...
为了便于识别和美观,要求现场手写字尽量符合标准字体模板(Times New Roman)的要求。标准字体模板如表5-196所示。 表5-196 标准字体模板 0 1 2 3 4 5 6 7 8 9 A B C D E F G H I J K L M N O P Q R S T U V W X Y Z 字的大小可根据数字或字母的数量灵活处理。当填写有汉字的...
解这个方程,我们得到: [ (rpm)^2 = \frac{12000 \times 9.81}{1.118 \times 10^{-5} \times 15} ] [ (rpm)^2 \approx 70620612.09 ] [ rpm \approx \sqrt{70620612.09} ] [ rpm \approx 8399.44 ] 所以,在旋转半径为15厘米的情况下,大约需要8400 rpm(四舍五入到最近的整数)来达到12000g的离心...
(3)W=Fs=1.5\times 10^6N\times 30\times 10^3m=4.5\times 10^1^0J (4)根据二力平衡及相互作用力有:F_压=G=mg=3* 10^3kg* 10N/kg* 3* 10^4N P_2=((F_压) )=((3* 10^4N)(0.06m^2) )=5* 10^5Pa (1)根据公式F=G=mg计算浮力。 (2)根据公式P=ρ gh计算压强。 (3)根据公式...
G.SKILL International Enterprise Co., Ltd., the world's leading brand of performance overclock memory and PC components, is excited to announce that four extreme overclockers - BenchMarc from US, OGS from Greece, Dreadzone from Australia, and CENS from Germany have all successfully shattered the...
the LS12000 puts internal patterns up on the screen. I began my calibration process using these internal patterns instead of those provided by my Murideo Six-G but quickly ran into problems. After using the internal color point patterns, I ran Calman with the Murideo patterns and immediately sa...
1 7 6 \times 1 0 ^ { 8 } N $$ (2)船满载时受的浮力$$ F _ { 3 } = G _ { 3 } = m _ { 3 } g $$, 船漂浮,则满载时的重力$$ G _ { 总 } = F _ { 0 } = G _ { 1 } = m _ { 1 } g $$ 若满载时,所装物品的质量为5000吨,则该船自身 的重力:$$ G = G...
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8 N $$ $$ / k g = 1 . 1 7 6 \times 1 0 ^ { 8 } N $$ 该船自身的质量: $$ m _ { n } = m _ { 3 } - m _ { n } = 1 2 0 0 0 t - 5 0 0 0 t $$; $$ = 7 0 0 0 t $$ 因为$$ \rho _ { 4 水 } > \rho _ { 丁水 } $$,根据$$ F _ { ...