【解析】解: $$ 1 6 0 \times 1 2 0 0 0 \times 1 4 0 0 0 \\ = 1 9 2 0 0 0 0 \times 1 4 0 0 0 \\ = 2 6 8 8 0 0 0 0 0 0 0 ( 克 ) $$ $$ 2 6 8 8 0 0 0 0 0 0 0 克 = 2 6 8 8 0 吨 $$ 答:今年新购私人轿车一年共排放26880吨二氧化 碳.【...
为了便于识别和美观,要求现场手写字尽量符合标准字体模板(Times New Roman)的要求。标准字体模板如表4-241所示。 表4-241 标准字体模板 0 1 2 3 4 5 6 7 8 9 A B C D E F G H I J K L M N O P Q R S T U V W X Y Z 字的大小可根据数字或字母的数量灵活处理。当填写有汉字的...
9 \% , $$ 油脂:$$ \frac { 3 7 . 7 k J \cdot g ^ { - 1 } \times 6 5 g } { 1 2 0 0 0 k J } \times 1 0 0 \% \approx 2 0 . 4 \% 。 $$ 结果一 题目 【题目】已知某人每日所需热量为12000kJ,每克糖类、蛋白质、油脂在人体内氧化所提供的热量分别为16.7kJ、16.7kJ...
RUN(G)/ALM(R)/OFL(Y) Running status indicator Green Steady on The card has been powered on but the system software is not running. Green Blinking once every 2 seconds (0.5 Hz) The card is working properly. Green Blinking four times every second (4 Hz) The card is loading the system...
现在,将 (g = 12000) 和 (R = 15.24) 厘米代入公式,并解出rpm: [ 12000 = 15.24 \times \left( \frac{2\pi \times \text{rpm}}{60} \right)^2 ] 首先,将公式简化并解出rpm的平方: [ \frac{12000}{15.24} = \left( \frac{2\pi \times \text{rpm}}{60} \right)^2 ] [ 787.42 \app...
1 6 0 g = 0 . 1 6 k g $$ $$ 1 4 4 0 0 0 0 0 0 \times 0 . 1 6 = 2 3 0 4 0 0 0 0 ( 千克 ) $$ $$ 2 3 0 4 0 0 0 0 千克 = 2 3 0 4 0 吨 $$ $$ 3 . 1 4 4 0 0 0 0 0 0 \div 1 0 0 \times 8 \\ = 1 4 4 0 0 0 0 \times 8 \\...
(2分) 3(1)(2)(3)①②(4) 4尺寸为、质量为2.76kg的普通实心砖放在水平地面上,则实心砖对地面的最小压强为___Pa.(g取10N/kg) 5尺寸为$240mm\times 15mm\times 50mm$、质量为$2.76kg$的普通实心砖放在水平地面上,则实心砖对地面的最小压强为___$Pa.(g$取$10N/kg)$ 反馈...
RUN(G)/ALM(R)/OFL(Y)Running status indicatorGreenSteady onThe card has been powered on but the system software is not running. GreenBlinking once every 2 seconds (0.5 Hz)The card is working properly. GreenBlinking four times every second (4 Hz)The card is loading the system software or...
RUN(G)/ALM(R)/OFL(Y) Running status indicator Green Steady on The card has been powered on but the system software is not running. Green Fast blinking (4 Hz) The card is loading the system software or is resetting. Green Slow blinking (0.5 Hz) The card software is running ...
1 7 6 \times 1 0 ^ { 8 } N $$ (2)船满载时受的浮力$$ F _ { 3 } = G _ { 3 } = m _ { 3 } g $$, 船漂浮,则满载时的重力$$ G _ { 总 } = F _ { 0 } = G _ { 1 } = m _ { 1 } g $$ 若满载时,所装物品的质量为5000吨,则该船自身 的重力:$$ G = G...