测试点6要求输出0,也就是多项式每一项相加减抵消了。 附代码: #include <iostream> using namespace std; struct Node{ int expn;//表示指数 double coef;//表示系数 Node*next; }; void InitList(Node*L,int n){ for(int i=0;i<n;i++){ Node*a=(Node*)malloc(sizeof(Node)); cin>>a->expn...
PAT甲级1002A+BforPolynomials（25分）附测试点6段错误原因 This time, you are supposed to find A+B where A and B are two polynomials.Input Specification:Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial:K N1a N1N2a ...
//map<int,double>::const_iterator 类似于指针,它其实叫做迭代器。 for(map<int,double>::const_iterator m_it=s.begin();m_it!=s.end();m_it++)//计算A+B多项式的项数 { if(m_it->second!=0.0&&m_it->second!=-0.0)//注意数据类型 i1++; } printf("%d",i1); for(map<int,double>::...
3 2 1.5 1 2.9 0 3.2 注意点: 1.输出格式 2.不要输出相加系数为零的项,完全抵消的话,输出0; 3.注意数组越界问题(我因为数组范围太小, 第二个测试点一直无法通过,但是报的是答案错误而不是段错误,导致我看了好久的程序, 后来输入允许的最多项后, vs2008 报出stack around the variable “” was corrup...
1002. A+B for Polynomials (25) 时间限制 400 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue This time, you are supposed to find A+B where A and B are two polynomials. Input Each input file contains one test case. Each case occupies 2 lines, and each li...
This time, you are supposed to find A+B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial: K N1 aN1 N2 aN2 … NK aNK where K is the number of nonzero...
输入格式:每个测试输入包含1个测试用例,即给出自然数n的值。这里保证n小于10100。 输出格式:在一行内输出n的各位数字之和的每一位,拼音数字间有1 空格,但一...PTA1002 PTA1002 问题描述: This time, you are supposed to find A+B where A and B are two polynomials. Input Specification: Each input ...