解析 5.解析:依题意得2lg(2x一1)=lg2+lg(2x+-|||-3),-|||-所以(2x一1)2=2(2x+3),-|||-所以(2x)2一4·2x-5=0,-|||-所以(2x一5)(2x十1)=0,-|||-所以2x=5或2x=一1(舍),-|||-所以x=log25.-|||-答案:B 反馈 收藏 ...
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2x-5 x+2)≤0,得0< 2x-5 x+2≤1,解得: 5 2<x≤7.(1)A={x|lg( 2x-5 x+2)≤0}={x| 5 2<x≤7},又U=R,∴∁UA={x|x ≤ 5 2或x>7};(2)∵A={x| 5 2<x≤7},B={x|x7;(3)C={x|m+1≤x≤2m-1},由C⊆A,若m+1>2m-1...
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对数方程(要求过程)(注:log2_x 表示 以 2为底 X的对数,以此类推)解方程e^x=4 lnx=6ln(2x-1)=1e(3x+5)=10ln(e^3-x)=8lnx=ln4+ln7ln(lnx)=24^x-2^(x+1)=3log2_x+ log4_x+log8_x=11求定义域f(x)=lg(2+5x)f(x)=log2_(10-3x)h(x)=lnx+ln(2
结果一 题目 (2)对数式1g(2x-1)中实数x的取值范围是, 答案 (2)由题意可知对数式1g(2x-1)中的真数大于0,即 2x-10 ,解得x1/2,所以x的取值范围是 (1/2,+∞)2) (1/2,+∞)相关推荐 1(2)对数式1g(2x-1)中实数x的取值范围是, 反馈 收藏 ...
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lg(2x-1)2-lg(x-3)2=2. 答案 ∵lg(2x-1)2-lg(x-3)2=2,∴lg(2x−1x−3)2=2,∴2lg2x−1x−3=2,或2lg1−2xx−3=2∴2x−1x−3=10,或1−2xx−3=10,解得x=298,或x=3112.经检验,得x=298或x=3112都是原方程的解.相关...
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+2 x2+x-2+3 的值. 试题答案 在线课程 分析:(1)计算 lg2+lg5-lg8 lg50-lg40 的值,由其形式可以看出,需要用对数的运算性质进行化简求值; (2)由其形式可以看出,需要先用立方差公式对表达式展开表示成x 1 2 +y 1 2 函数的形式,再代入值求解. ...