解答一 举报 (x+y)²-16(x-y)²=[(x+y)+4(x-y)][(x+y)-4(x-y)]=(x+y+4x-4y)(x+y-4x+4y)=(5x-3y)(5y-3x) 明白请采纳,有疑问请追问!有新问题请求助,谢谢! 解析看不懂?免费查看同类题视频解析查看解答 相似问题 锛坸-2y)虏锛坸虏+4y虏锛壜诧纸x+2y锛壜 具体算式 锛?X-...
答案解析 查看更多优质解析 解答一 举报 (x+y)²-16(x-y)²=[(x+y)+4(x-y)][(x+y)-4(x-y)]=(x+y+4x-4y)(x+y-4x+4y)=(5x-3y)(5y-3x) 明白请采纳,有疑问请追问!有新问题请求助,谢谢! 解析看不懂?免费查看同类题视频解析查看解答 ...
(x+y)²-16(x-y)²=[(x+y)+4(x-y)][(x+y)-4(x-y)]=(x+y+4x-4y)(x+y-4x+4y)=(5x-3y)(5y-3x)明白请采纳，有疑问请追问！有新问题请求助，谢谢!
锛坸锛寉锛夋弧瓒硘x|+|y|=1,(x-1)虏+y虏链（x，y）满足|x|+|y|=1,(x-1)²+y²...
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答：f(x)=ax^2-bx恒过原点（0,0）-4<=f(1)<=-1 -1<=f(2)<=5 所以：-4<=f(1)=a-b<=-1 -1<=f(2)=4a-2b<=5 所以：1<=-(a-b)<=4 以上两式相加得：1-1<=4a-2b-(a-b)<=4+5 所以：0<=3a-b<=9 因为：f(3)=9a-3b=3(3a-b)所以：0<=f(3)<=27 ...
恩，有道理