∠PBC+∠PCB= 1 2(∠DBC+∠ECB)=115°,∴∠P=65°.同理得:(2)45°;(3)40°(4)∠P=90°- 1 2∠A.理由如下:∵BP平分∠DBC,CP平分∠BCE,∴∠DBC=2∠CBP,∠BCE=2∠BCP又∵∠DBC=∠A+∠ACB∠BCE=∠A+∠ABC,∴2∠CBP=∠A+∠ACB,2∠BCP=∠A+∠ABC,∴2∠CBP+2∠BCP=∠A+∠ACB+∠A...