printf("你输入的矩阵如下：\n");for(i=0;i<3;i++){ for(j=0;j<3;j++)printf("%d ",A[i][j]);printf("\n");} printf("主对角线元素之积为：%d\n",(A[0][0]*A[1][1]*A[2][2]));printf("次对角线元素之积为：%d\n",(A[0][2]*A[1][1]*A[2][0]));r...