步骤1:理解斐波那契数列的定义 斐波那契数列是一个递归定义的数列,它的前两项是0和1,从第三项开始,每一项等于前两项之和。简单来说,即: F(0) = 0 F(1) = 1 F(n) = F(n-1) + F(n-2), (当 n >= 2) 步骤2:设定循环,准备存储结果 为了存储前10个斐波那契数,我们可以使用一个列表。在Python...
if n==0 or n==1: return n else: return fab(n-1)+fab(n-2) fab(6) >>8 1. 2. 3. 4. 5. 6. 7. 8. 通过循环打印斐波那契数列: s = [] import numpy as np for n in range(7): if n==0 or n==1: s.extend([n]) print(n) else: s.extend([s[n-1]+s[n-2]]) pr...
if n <= 0: return [] elif n == 1: return [0] else: sequence = [0, 1] while len(sequence) < n: next_value = sequence[-1] + sequence[-2] sequence.append(next_value) return sequence result = fibonacci(10) print(result) ``` 查看本题试卷 python计算斐波那契数列的前10项 110阅读...
a, b = 0, 1 while b < 10000000000000000000000000000000000000000000000000000000000000000000000000000000000000000: print(b) a, b = b, a+b 打印结果如下: 1 1 2 3 5 8 13 21 34 55 89 144 233 377 610 987 1597 2584 4181 6765 10946 17711 28657 46368 75025 121393 196418 317811 514229 832040 1346269...