for j in xrange((100 - i * 1) / 5 + 1):for k in xrange ((100 - i * 1 + j * 5) / 10 + 1):if i * 1 + j * 5 + k * 10 == 100:print "1:", i, "5:", j, "10:", k cnt += 1 print cnt 结果如下，总共121种 1: 0 5: 0 10: 10 1: 0 5...