基础有效高度h 0 =h-40(mm)抗冲切面积A t =(2b C +2h C +4h 0 )h 0 (m 2 ) 冲切面积A l =A-B(h C +2h 0 )(m 2 )抗冲切力F t =0.6f t A t (KN) 冲切力F l =p Smax A l (KN)验算F l ≤F t 抗剪切面积A V =Bh 0 -(h-h 1 )(B-b C )/2(m 2 )剪切力V=p...