left,right=1e10;staticint[] a =newint[100005],b =newint[100005];publicstaticvoidmain(String[] args){Scanner sc=newScanner(System.in);n = sc.nextInt();p = sc.nextInt();for(inti=0;i<n;i++){a[i] = sc.nextInt();b[i] = sc.nextInt();sum+=a[i];}if(sum<=p){System....
https://vjudge.net/contest/295090#problem/B 题意:给出一个序列,在该序列找一个数m,问该在该序列第几小。 解法一:直接统计比m小的数,O(n) 解法二:排序,再二分注意要mid-1,因为如果在该序列中找不到该数时会死循环,O(nlogn) 解法三:通过一次遍历交换将比a[Mid]小的数放到a[Mid]左边,比a[Mid...
static int[] a = new int[100005],b = new int[100005];public static void main(String[] args) { Scanner sc= new Scanner (System.in);n = sc.nextInt();p = sc.nextInt();for(int i=0;i<n;i++){ a[i] = sc.nextInt();b[i] = sc.nextInt();sum+=a[i];} if(sum<=p){...
intn; doublea ; doubleb[4]; doubleans; boolcheck(doublex){ b[1] = a ; b[2] = x ; for(inti = 3 ; i <= n ; i++){ b[3] = (2.0*b[2]+2) - b[1]; b[1] = b[2]; b[2] = b[3]; if(b[3] < 0)returnfalse; } ans = b[3]; returntrue; } voidsolve(){...
计算A[i]+B[j]+C[k]=x 转换为A[i]+B[i]=x-C[k] ,这样在A[i]+B[i]中二分查找,x-C[k] ,不会超时。 题目来源: http://acm.hdu.edu.cn/showproblem.php?pid=2141 Can you find it? Time Limit: 10000/3000 MS (Java/Others) Memory Limit: 32768/10000 K (Java/Others) ...