1. Identify the functions for integration by parts: We will choose: - u=log(1+x2) (the logarithmic function) - dv=dx (the differential of x) 2. Differentiate and integrate: - Differentiate u: du=ddx(log(1+x2))dx=2x1+x2dx - Integrate dv: v=∫dx=x 3. Apply the integration by...
相关知识点: 试题来源: 解析 [解析]1利用定积分的几何意义求定积分的解法突破在于:一般情况下,定积分f(x)dx的值的几何意义是介于x轴、函数f(x)的图像以及直线x=a,x=b之间各部分面积的代数和,在x轴上方的积分值取正号,在x轴下方的积分值取负号。 反馈 收藏 ...
D−1 ∫1−1(x2+x+3)dx View Solution The value of the integral∫1−1(x−[2x])dx,is View Solution ∫1−1|2x+1|dx View Solution ∫1−1e2xdx View Solution The integral∫1−1|x+2|x+2dxis equal to View Solution ...
结果1 题目2.求下列导数(1) (c1)/(x1.x) d/(dx)∫_0^xsint dt:(2) d/(dx)∫_1^(x^2)1/(1+t^2)dt(3d/(dx)∫_x^5√(1+t^2dt)f;) d/(dx)∫_(√x^(x^2)e^(-1^2) 相关知识点: 试题来源: 解析 2. (1)sinx:(2)(2x)/(1+x^4):(3)-√(x^2+1)⋅...
这意味着函数 f(x) = 1 在区间 [a, b] 上的定积分等于该区间的长度。例如，如果区间是 [0, 2]，则定积分 ∫_0^2 1 dx = 2 - 0 = 2。总结来说，定积分 ∫ 1 dx 的值为 x + C，其中 C 是积分常数。对于函数 f(x) = 1，其定积分在任意区间 [a, b] 上的值为 ...
মান নির্ণয় করো : inta^b x^2 dx 00:58 মান নির্ণয় করো : int0^1 3^x dx 00:57 মান নির্ণয় করো : int1^2 4^x dx 01:14 int-2^2 x^2 dx নির্ণয় করো 01:...
结果一 题目 【题目】交换积分次序∫_1^2dx∫_(2-x)^(√(2x-x^2))f(x,y)dy= 答案 【解析】∫_0^1dy∫_(2-y)^(1+√(1-y^2))f(x,y)dx相关推荐 1【题目】交换积分次序∫_1^2dx∫_(2-x)^(√(2x-x^2))f(x,y)dy= 反馈 收藏 ...
{eq}\int {x{{\left( {1 + 2{x^2}} \right)}^2}} \ dx {/eq} Indefinite Integrals The indefinite integrals are different from the other integral forms as the upper and the lower limits in these indefinite integrals are not defined; that is, {eq}\int {f\left( x \...
【解析】解: (1)$$ \int _ { 0 } ^ { 1 } 2 x d x = 1 $$的几何意义是:$$ y = 2 x , x = 1 , y = 0 $$围成 图形的面积为1. 综上所述,结论是:几何意义是:$$ y = 2 x , x = 1 , y = 0 $$围 成图形的面积为1. (2)$$ \int _ { - 1 }...
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